2.00 Unknown platform Driver
This is because the horizontal velocity stays the same the whole time, and the vertical velocity at impact is the. Is acceleration due to gravity 10 m/s^2 or m/s^2? My teacher says it is 10 but Dave says it is Reply. sudo ~/RetroPie-Setup/ Unknown platform - please It looks like by setting it as raspberry pi 2 it may work but I am.
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2.00 Unknown platform Driver
So how do we solve this with math? Let's write down what we know. What we know is that horizontally 2.00 Unknown platform person started off with an initial velocity. V initial in the x, I could have written i for initial, but I wrote zero for v naught in the x, it still means initial velocity is five meters per second.
Horizontally launched projectile (video) Khan Academy
And we don't know anything else in the 2.00 Unknown platform direction. You might think 30 meters is the displacement in the x direction, but that's a vertical distance. This 2.00 Unknown platform not telling us anything about this horizontal distance. This horizontal distance or displacement is what we want to know. This horizontal displacement in the x direction, that's what we want to solve for, so we're gonna declare our ignorance, write that here. We don't know how to find it but we want to know that we do want to find so I'm gonna write it there.
Elokuvaosakeyhtiö Suomi Oy - "The Unknown Platform"
How about in the y direction, what do we know? We know that the, alright, now we're gonna use this You might want to say that delta y is positive 30 but you would be wrong, and the reason is, this person fell downward 30 meters. Think about it. They started at 2.00 Unknown platform top 2.00 Unknown platform the cliff, ended at the bottom of the cliff.
It means this person is going to end up 2.00 Unknown platform where they started, 30 meters below where they started. So this has to be negative 30 meters for the displacement, assuming you're treating downward as negative which is typically the convention shows that downward is negative and leftward is negative.
2.00 Unknown platform So if you choose downward as negative, this has to be a negative displacement. What else do we know vertically? Well, for a freely flying object we know that the acceleration vertically is always gonna be negative 9.
Now, here's the point where people get stumped, and here's the part where people make a mistake. They want to say that the initial velocity in the y 2.00 Unknown platform is five meters per second. I mean people are just dying to stick these five meters per second into here because that's the velocity that you were given.
But this was a horizontal velocity. That's why this is called horizontally launched projectile motion, not vertically launched projectile motion. So think about it. The initial velocity in the vertical direction here was zero, there was no initial 2.00 Unknown platform velocity.
Projectile at an angle
This 2.00 Unknown platform was not launched vertically up or vertically down, this person was just launched straight horizontally, and so the initial velocity in the vertical direction is just zero. People don't like that. They're like "hold on a minute. But that's after you leave the cliff. We're talking about right as you leave the 2.00 Unknown platform.
Unknown platform error? - RetroPie Forum
2.00 Unknown platform That moment you left the cliff there was only horizontal velocity, which means you started with no initial vertical velocity. So this is the part people get confused by because this is not given to you explicitly in the problem. The 2.00 Unknown platform won't say, "Find the distance for a cliff diver "assuming the initial velocity in the y direction was zero. So that's the trick. Don't fall for it now you know how to deal with it.
So we want to solve for displacement in the x direction, 2.00 Unknown platform how many variables we know in the y direction? I mean we know all of this. This is good. But we can't use this to solve directly for the displacement in the x direction.
We need to use this to solve for the time because the time is gonna be the same for the x direction and the y direction. So I find the time I can plug back in over to there, because think about it, the time it takes 2.00 Unknown platform this trip is gonna be the time it takes for this trip. It doesn't matter whether I call it the x direction or y direction, time is the same for both directions.